Numerical To find the Total Time For Execution of Instruction.

Problem: Find the Total Time for Execution of Instruction OUT 05H. The given clock frequency(f) is 2 MHz.
=> Solution:
Here Given,
Internal Clock Frequency (f) = 2 MHz = 2*10^6 Hz
We know,
Time Period(T) = 1/f
                         = 1/(2*10^6)
                         = 0.5 microsecond
The total T-States of the given instruction OUT 05H is 10T
Hence,
Total Time for Execution of Instruction = 10 * 0.5
                                                                = 5 microsecond

Points to Remember:

• If external clock frequency is given instead of internal clock frequency, then to find the internal clock frequency divide the external clock frequency by 2.
• If neither of the internal and external clock frequency is mentioned then assume the give clock frequency as internal clock frequency.

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